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5(x-4y+2c)=0 equation

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Numerical solution:

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The solution

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5*(x - 4*y + 2*c) = 0
$$5 \left(2 c + \left(x - 4 y\right)\right) = 0$$
Detail solution
Given the linear equation:
5*(x-4*y+2*c) = 0

Expand brackets in the left part
5*x-5*4*y+5*2*c = 0

Looking for similar summands in the left part:
-20*y + 5*x + 10*c = 0

Move the summands with the other variables
from left part to right part, we given:
$$10 c + 5 x = 20 y$$
Divide both parts of the equation by (5*x + 10*c)/x
x = 20*y / ((5*x + 10*c)/x)

We get the answer: x = -2*c + 4*y
The graph
Rapid solution [src]
x1 = -2*re(c) + 4*re(y) + I*(-2*im(c) + 4*im(y))
$$x_{1} = i \left(- 2 \operatorname{im}{\left(c\right)} + 4 \operatorname{im}{\left(y\right)}\right) - 2 \operatorname{re}{\left(c\right)} + 4 \operatorname{re}{\left(y\right)}$$
x1 = i*(-2*im(c) + 4*im(y)) - 2*re(c) + 4*re(y)
Sum and product of roots [src]
sum
-2*re(c) + 4*re(y) + I*(-2*im(c) + 4*im(y))
$$i \left(- 2 \operatorname{im}{\left(c\right)} + 4 \operatorname{im}{\left(y\right)}\right) - 2 \operatorname{re}{\left(c\right)} + 4 \operatorname{re}{\left(y\right)}$$
=
-2*re(c) + 4*re(y) + I*(-2*im(c) + 4*im(y))
$$i \left(- 2 \operatorname{im}{\left(c\right)} + 4 \operatorname{im}{\left(y\right)}\right) - 2 \operatorname{re}{\left(c\right)} + 4 \operatorname{re}{\left(y\right)}$$
product
-2*re(c) + 4*re(y) + I*(-2*im(c) + 4*im(y))
$$i \left(- 2 \operatorname{im}{\left(c\right)} + 4 \operatorname{im}{\left(y\right)}\right) - 2 \operatorname{re}{\left(c\right)} + 4 \operatorname{re}{\left(y\right)}$$
=
-2*re(c) + 4*re(y) + 2*I*(-im(c) + 2*im(y))
$$2 i \left(- \operatorname{im}{\left(c\right)} + 2 \operatorname{im}{\left(y\right)}\right) - 2 \operatorname{re}{\left(c\right)} + 4 \operatorname{re}{\left(y\right)}$$
-2*re(c) + 4*re(y) + 2*i*(-im(c) + 2*im(y))