(4x-3)(4x+3)-2x(8x-1)=0 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the equation:
(4*x-3)*(4*x+3)-2*x*(8*x-1) = 0
Expand expressions:
- 9 + 16*x^2 - 2*x*(8*x - 1) = 0
- 9 + 16*x^2 - 16*x^2 + 2*x = 0
Reducing, you get:
-9 + 2*x = 0
Move free summands (without x)
from left part to right part, we given:
$$2 x = 9$$
Divide both parts of the equation by 2
x = 9 / (2)
We get the answer: x = 9/2
Sum and product of roots
[src]
$$\frac{9}{2}$$
$$\frac{9}{2}$$
$$\frac{9}{2}$$
$$\frac{9}{2}$$