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(4x-3)(4x+3)-2x(8x-1)=0 equation

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Numerical solution:

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The solution

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(4*x - 3)*(4*x + 3) - 2*x*(8*x - 1) = 0
$$- 2 x \left(8 x - 1\right) + \left(4 x - 3\right) \left(4 x + 3\right) = 0$$
Detail solution
Given the equation:
(4*x-3)*(4*x+3)-2*x*(8*x-1) = 0

Expand expressions:
- 9 + 16*x^2 - 2*x*(8*x - 1) = 0

- 9 + 16*x^2 - 16*x^2 + 2*x = 0

Reducing, you get:
-9 + 2*x = 0

Move free summands (without x)
from left part to right part, we given:
$$2 x = 9$$
Divide both parts of the equation by 2
x = 9 / (2)

We get the answer: x = 9/2
The graph
Rapid solution [src]
x1 = 9/2
$$x_{1} = \frac{9}{2}$$
x1 = 9/2
Sum and product of roots [src]
sum
9/2
$$\frac{9}{2}$$
=
9/2
$$\frac{9}{2}$$
product
9/2
$$\frac{9}{2}$$
=
9/2
$$\frac{9}{2}$$
9/2
Numerical answer [src]
x1 = 4.5
x1 = 4.5