Mister Exam
Other calculators
-
How to use it?
- Equation:
-
Equation (x-4)/x=(2*x+10)/(x+4)
-
Equation 9*x^2-1=0
-
Equation 2*sin(x)*cos(x)=0
-
Equation 3x-2=7x+6
- Express {x} in terms of y where:
- -1*x+1*y=-13
- 9*x-1*y=-10
- -19*x+20*y=-11
- -10*x+4*y=-7
- Limit of the function:
-
21
- Sum of series:
-
21
-
Identical expressions
- (4p- two)(three p- one)- three (3-p)-1 two p^2= twenty-one
- (4p minus 2)(3p minus 1) minus 3(3 minus p) minus 12p squared equally 21
- (4p minus two)(three p minus one) minus three (3 minus p) minus 1 two p squared equally twenty minus one
- (4p-2)(3p-1)-3(3-p)-12p2=21
- 4p-23p-1-33-p-12p2=21
- (4p-2)(3p-1)-3(3-p)-12p²=21
- (4p-2)(3p-1)-3(3-p)-12p to the power of 2=21
- 4p-23p-1-33-p-12p^2=21
-
Similar expressions
- x=(26.88*1*sqrt(5.4343-1.65*10^-7*x^2-5.5*10^-7*7.5*x-6.3*10^-7*7.5^2-0.627*7.5-0.2*10^-5*x)-0.023*7.5)/0.0112
- (4p-2)(3p-1)-3(3-p)+12p^2=21
- (4p-2)(3p+1)-3(3-p)-12p^2=21
- 2*(102-b)+b=128
- 2,031+0,54+(1*(3,7)^2)/(2*9,8*(0,54)^2(1,5+1*0,54)^2)=x+(1,1*(3,7)^2)/(2*9,8*x^2(1,5+1*x)^2*(0,85)^2)
- (4p-2)(3p-1)+3(3-p)-12p^2=21
- (4p+2)(3p-1)-3(3-p)-12p^2=21
- (4p-2)(3p-1)-3(3+p)-12p^2=21
(4p-2)(3p-1)-3(3-p)-12p^2=21 equation
The teacher will be very surprised to see your correct solution 😉
The solution
You have entered
[src]
2 (4*p - 2)*(3*p - 1) - 3*(3 - p) - 12*p = 21
$$- 12 p^{2} + \left(- 3 \left(3 - p\right) + \left(3 p - 1\right) \left(4 p - 2\right)\right) = 21$$
Detail solution
Given the equation:
Expand expressions:
Reducing, you get:
Move free summands (without p)
from left part to right part, we given:
$$- 7 p = 28$$
Divide both parts of the equation by -7
We get the answer: p = -4
(4*p-2)*(3*p-1)-3*(3-p)-12*p^2 = 21
Expand expressions:
- 7 - 7*p + 12*p^2 - 12*p^2 = 21
Reducing, you get:
-28 - 7*p = 0
Move free summands (without p)
from left part to right part, we given:
$$- 7 p = 28$$
Divide both parts of the equation by -7
p = 28 / (-7)
We get the answer: p = -4