Mister Exam

Lang:

How to use it?
Equation:
Equation log3(5-x)+log3(-1-x)=3
Equation 7x^2+8-13x=8x-6
Equation arctg(x/y)
Equation (4sin^2x-3)*sqrt(x^2-36pi^2)=o
Express {x} in terms of y where:
15*x-17*y=19
9*x-8*y=6
15*x+15*y=16
8*x+7*y=-13
Identical expressions
(4sin^ two x- three)*sqrt(x^ two -36pi^2)=o
(4 sinus of squared x minus 3) multiply by square root of (x squared minus 36 Pi squared ) equally o
(4 sinus of to the power of two x minus three) multiply by square root of (x to the power of two minus 36 Pi squared ) equally o
(4sin^2x-3)*√(x^2-36pi^2)=o
(4sin2x-3)*sqrt(x2-36pi2)=o
4sin2x-3*sqrtx2-36pi2=o
(4sin²x-3)*sqrt(x²-36pi²)=o
(4sin to the power of 2x-3)*sqrt(x to the power of 2-36pi to the power of 2)=o
(4sin^2x-3)sqrt(x^2-36pi^2)=o
(4sin2x-3)sqrt(x2-36pi2)=o
4sin2x-3sqrtx2-36pi2=o
4sin^2x-3sqrtx^2-36pi^2=o
Similar expressions
(4sin^2x-3)*sqrt(x^2+36pi^2)=o
(4sin^2x+3)*sqrt(x^2-36pi^2)=o

(4sin^2x-3)*sqrt(x^2-36pi^2)=o equation

The teacher will be very surprised to see your correct solution 😉

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/     2       \   /  2        2     
\4*sin (x) - 3/*\/  x  - 36*pi   = o

$$\sqrt{x^{2} - 36 \pi^{2}} \left(4 \sin^{2}{\left(x \right)} - 3\right) = o$$

Simplify

The graph