4cosz+5=0 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the equation
$$4 \cos{\left(z \right)} + 5 = 0$$
- this is the simplest trigonometric equation
Move 5 to right part of the equation
with the change of sign in 5
We get:
$$4 \cos{\left(z \right)} = -5$$
Divide both parts of the equation by 4
The equation is transformed to
$$\cos{\left(z \right)} = - \frac{5}{4}$$
As right part of the equation
modulo =
True
but cos
can no be more than 1 or less than -1
so the solution of the equation d'not exist.
z1 = -re(acos(-5/4)) + 2*pi - I*im(acos(-5/4))
$$z_{1} = - \operatorname{re}{\left(\operatorname{acos}{\left(- \frac{5}{4} \right)}\right)} + 2 \pi - i \operatorname{im}{\left(\operatorname{acos}{\left(- \frac{5}{4} \right)}\right)}$$
z2 = I*im(acos(-5/4)) + re(acos(-5/4))
$$z_{2} = \operatorname{re}{\left(\operatorname{acos}{\left(- \frac{5}{4} \right)}\right)} + i \operatorname{im}{\left(\operatorname{acos}{\left(- \frac{5}{4} \right)}\right)}$$
z2 = re(acos(-5/4)) + i*im(acos(-5/4))
Sum and product of roots
[src]
-re(acos(-5/4)) + 2*pi - I*im(acos(-5/4)) + I*im(acos(-5/4)) + re(acos(-5/4))
$$\left(\operatorname{re}{\left(\operatorname{acos}{\left(- \frac{5}{4} \right)}\right)} + i \operatorname{im}{\left(\operatorname{acos}{\left(- \frac{5}{4} \right)}\right)}\right) + \left(- \operatorname{re}{\left(\operatorname{acos}{\left(- \frac{5}{4} \right)}\right)} + 2 \pi - i \operatorname{im}{\left(\operatorname{acos}{\left(- \frac{5}{4} \right)}\right)}\right)$$
$$2 \pi$$
(-re(acos(-5/4)) + 2*pi - I*im(acos(-5/4)))*(I*im(acos(-5/4)) + re(acos(-5/4)))
$$\left(\operatorname{re}{\left(\operatorname{acos}{\left(- \frac{5}{4} \right)}\right)} + i \operatorname{im}{\left(\operatorname{acos}{\left(- \frac{5}{4} \right)}\right)}\right) \left(- \operatorname{re}{\left(\operatorname{acos}{\left(- \frac{5}{4} \right)}\right)} + 2 \pi - i \operatorname{im}{\left(\operatorname{acos}{\left(- \frac{5}{4} \right)}\right)}\right)$$
-(I*im(acos(-5/4)) + re(acos(-5/4)))*(-2*pi + I*im(acos(-5/4)) + re(acos(-5/4)))
$$- \left(\operatorname{re}{\left(\operatorname{acos}{\left(- \frac{5}{4} \right)}\right)} + i \operatorname{im}{\left(\operatorname{acos}{\left(- \frac{5}{4} \right)}\right)}\right) \left(- 2 \pi + \operatorname{re}{\left(\operatorname{acos}{\left(- \frac{5}{4} \right)}\right)} + i \operatorname{im}{\left(\operatorname{acos}{\left(- \frac{5}{4} \right)}\right)}\right)$$
-(i*im(acos(-5/4)) + re(acos(-5/4)))*(-2*pi + i*im(acos(-5/4)) + re(acos(-5/4)))
z1 = 3.14159265358979 + 0.693147180559945*i
z2 = 3.14159265358979 - 0.693147180559945*i
z2 = 3.14159265358979 - 0.693147180559945*i