A quadratic equation can be solved using the discriminant. The roots of the quadratic equation: $$x_{1} = \frac{\sqrt{D} - b}{2 a}$$ $$x_{2} = \frac{- \sqrt{D} - b}{2 a}$$ where D = b^2 - 4*a*c - it is the discriminant. Because $$a = 3$$ $$b = 7$$ $$c = 2$$ , then
D = b^2 - 4 * a * c =
(7)^2 - 4 * (3) * (2) = 25
Because D > 0, then the equation has two roots.
x1 = (-b + sqrt(D)) / (2*a)
x2 = (-b - sqrt(D)) / (2*a)
or $$x_{1} = - \frac{1}{3}$$ $$x_{2} = -2$$
Vieta's Theorem
rewrite the equation $$\left(3 x^{2} + 7 x\right) + 2 = 0$$ of $$a x^{2} + b x + c = 0$$ as reduced quadratic equation $$x^{2} + \frac{b x}{a} + \frac{c}{a} = 0$$ $$x^{2} + \frac{7 x}{3} + \frac{2}{3} = 0$$ $$p x + q + x^{2} = 0$$ where $$p = \frac{b}{a}$$ $$p = \frac{7}{3}$$ $$q = \frac{c}{a}$$ $$q = \frac{2}{3}$$ Vieta Formulas $$x_{1} + x_{2} = - p$$ $$x_{1} x_{2} = q$$ $$x_{1} + x_{2} = - \frac{7}{3}$$ $$x_{1} x_{2} = \frac{2}{3}$$