Mister Exam
Other calculators
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How to use it?
- Equation:
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Equation (x-5)/2=2*(3x/7-1/2)/3
-
Equation cos(x/2)=(1/2)
-
Equation x^4-4*x^3-2*x^2+12*x+9=0
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Equation sin(x)=-1
- Express {x} in terms of y where:
- -6*x-17*y=14
- 4*x-18*y=-14
- -14*x-1*y=3
- 1*x-6*y=-19
- Integral of d{x}:
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3x^2-4x+1
- Derivative of:
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3x^2-4x+1
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Identical expressions
- 3x^ two -4x+ one
- 3x squared minus 4x plus 1
- 3x to the power of two minus 4x plus one
- 3x2-4x+1
- 3x²-4x+1
- 3x to the power of 2-4x+1
-
Similar expressions
- 3x^2-4x-1
- 3x^2+4x+1
3x^2-4x+1 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
This equation is of the form
A quadratic equation can be solved
using the discriminant.
The roots of the quadratic equation:
$$x_{1} = \frac{\sqrt{D} - b}{2 a}$$
$$x_{2} = \frac{- \sqrt{D} - b}{2 a}$$
where D = b^2 - 4*a*c - it is the discriminant.
Because
$$a = 3$$
$$b = -4$$
$$c = 1$$
, then
Because D > 0, then the equation has two roots.
or
$$x_{1} = 1$$
Simplify
$$x_{2} = \frac{1}{3}$$
Simplify
a*x^2 + b*x + c = 0
A quadratic equation can be solved
using the discriminant.
The roots of the quadratic equation:
$$x_{1} = \frac{\sqrt{D} - b}{2 a}$$
$$x_{2} = \frac{- \sqrt{D} - b}{2 a}$$
where D = b^2 - 4*a*c - it is the discriminant.
Because
$$a = 3$$
$$b = -4$$
$$c = 1$$
, then
D = b^2 - 4 * a * c =
(-4)^2 - 4 * (3) * (1) = 4
Because D > 0, then the equation has two roots.
x1 = (-b + sqrt(D)) / (2*a)
x2 = (-b - sqrt(D)) / (2*a)
or
$$x_{1} = 1$$
Simplify
$$x_{2} = \frac{1}{3}$$
Simplify
Vieta's Theorem
rewrite the equation
$$3 x^{2} - 4 x + 1 = 0$$
of
$$a x^{2} + b x + c = 0$$
as reduced quadratic equation
$$x^{2} + \frac{b x}{a} + \frac{c}{a} = 0$$
$$x^{2} - \frac{4 x}{3} + \frac{1}{3} = 0$$
$$p x + x^{2} + q = 0$$
where
$$p = \frac{b}{a}$$
$$p = - \frac{4}{3}$$
$$q = \frac{c}{a}$$
$$q = \frac{1}{3}$$
Vieta Formulas
$$x_{1} + x_{2} = - p$$
$$x_{1} x_{2} = q$$
$$x_{1} + x_{2} = \frac{4}{3}$$
$$x_{1} x_{2} = \frac{1}{3}$$
$$3 x^{2} - 4 x + 1 = 0$$
of
$$a x^{2} + b x + c = 0$$
as reduced quadratic equation
$$x^{2} + \frac{b x}{a} + \frac{c}{a} = 0$$
$$x^{2} - \frac{4 x}{3} + \frac{1}{3} = 0$$
$$p x + x^{2} + q = 0$$
where
$$p = \frac{b}{a}$$
$$p = - \frac{4}{3}$$
$$q = \frac{c}{a}$$
$$q = \frac{1}{3}$$
Vieta Formulas
$$x_{1} + x_{2} = - p$$
$$x_{1} x_{2} = q$$
$$x_{1} + x_{2} = \frac{4}{3}$$
$$x_{1} x_{2} = \frac{1}{3}$$
Sum and product of roots
[src]
sum
0 + 1/3 + 1
$$\left(0 + \frac{1}{3}\right) + 1$$
=
4/3
$$\frac{4}{3}$$
product
1*1/3*1
$$1 \cdot \frac{1}{3} \cdot 1$$
=
1/3
$$\frac{1}{3}$$
1/3
The graph