Mister Exam
Other calculators
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How to use it?
- Equation:
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Equation x^2-9x+20=0
-
Equation 3x-7(3x-4)=5(2x-7)
-
Equation cos*((pi(4x+48))/4)=-(sqrt(2)/2)
- Equation 2cos^3x-2cosx-sin^2x=0
- Express {x} in terms of y where:
- 10*x-1*y=10
- 15*x-17*y=19
- 9*x-8*y=6
- 15*x+15*y=16
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Identical expressions
- 3x- seven (3x- four)= five (2x- seven)
- 3x minus 7(3x minus 4) equally 5(2x minus 7)
- 3x minus seven (3x minus four) equally five (2x minus seven)
- 3x-73x-4=52x-7
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Similar expressions
- 3x-7(3x+4)=5(2x-7)
- 4x+9=5*(2x-7)-6x
- 2*log(5)^2*x-7*log(5)*x+3=0
- 4*x+9=5*(2*x-7)-6*x
- 3x-7(3x-4)=5(2x+7)
- 3x+7(3x-4)=5(2x-7)
3x-7(3x-4)=5(2x-7) equation
The teacher will be very surprised to see your correct solution 😉
The solution
You have entered
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3*x - 7*(3*x - 4) = 5*(2*x - 7)
$$3 x - 7 \left(3 x - 4\right) = 5 \left(2 x - 7\right)$$
Detail solution
Given the linear equation:
Expand brackets in the left part
Expand brackets in the right part
Looking for similar summands in the left part:
Move free summands (without x)
from left part to right part, we given:
$$- 18 x = 10 x - 63$$
Move the summands with the unknown x
from the right part to the left part:
$$\left(-28\right) x = -63$$
Divide both parts of the equation by -28
We get the answer: x = 9/4
3*x-7*(3*x-4) = 5*(2*x-7)
Expand brackets in the left part
3*x-7*3*x+7*4 = 5*(2*x-7)
Expand brackets in the right part
3*x-7*3*x+7*4 = 5*2*x-5*7
Looking for similar summands in the left part:
28 - 18*x = 5*2*x-5*7
Move free summands (without x)
from left part to right part, we given:
$$- 18 x = 10 x - 63$$
Move the summands with the unknown x
from the right part to the left part:
$$\left(-28\right) x = -63$$
Divide both parts of the equation by -28
x = -63 / (-28)
We get the answer: x = 9/4
Sum and product of roots
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sum
9/4
$$\frac{9}{4}$$
=
9/4
$$\frac{9}{4}$$
product
9/4
$$\frac{9}{4}$$
=
9/4
$$\frac{9}{4}$$
9/4
The graph