Mister Exam
Other calculators
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How to use it?
- Equation:
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Equation 3x-7(3x-4)=5(2x-7)
- Equation 2*log(5)^2*x-7*log(5)*x+3=0
- Equation √cos(2x)-sin(5x)=-2cosx
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Equation x^3-3x^2+2x=210
- Express {x} in terms of y where:
- -1*x-19*y=-10
- 4*x-16*y=6
- 5*x+5*y=20
- 10*x-1*y=10
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Identical expressions
- 3x- seven (3x- four)= five (2x- seven)
- 3x minus 7(3x minus 4) equally 5(2x minus 7)
- 3x minus seven (3x minus four) equally five (2x minus seven)
- 3x-73x-4=52x-7
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Similar expressions
- 4*x+9=5*(2*x-7)-6*x
- 4x+9=5*(2x-7)-6x
- 3x+7(3x-4)=5(2x-7)
- 2*log(5)^2*x-7*log(5)*x+3=0
- 3x-7(3x-4)=5(2x+7)
- 3x-7(3x+4)=5(2x-7)
3x-7(3x-4)=5(2x-7) equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the linear equation:
Expand brackets in the left part
Expand brackets in the right part
Looking for similar summands in the left part:
Move free summands (without x)
from left part to right part, we given:
Move the summands with the unknown x
from the right part to the left part:
Divide both parts of the equation by -28
We get the answer: x = 9/4
3*x-7*(3*x-4) = 5*(2*x-7)
Expand brackets in the left part
3*x-7*3*x+7*4 = 5*(2*x-7)
Expand brackets in the right part
3*x-7*3*x+7*4 = 5*2*x-5*7
Looking for similar summands in the left part:
28 - 18*x = 5*2*x-5*7
Move free summands (without x)
from left part to right part, we given:
Move the summands with the unknown x
from the right part to the left part:
Divide both parts of the equation by -28
x = -63 / (-28)
We get the answer: x = 9/4
The graph