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- Equation:
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Equation 4*x=24+x
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Equation 1/4*x^2-36=0
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Equation (3*x-1)=2
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Equation 12/x=3
- Express {x} in terms of y where:
- -9*x-6*y=12
- -2*x-18*y=10
- -6*x+11*y=-5
- -3*x-19*y=-9
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Identical expressions
- 3 two x+ ten (one ,2-14x)=-28x+ forty
- 32x plus 10(1,2 minus 14x) equally minus 28x plus 40
- 3 two x plus ten (one ,2 minus 14x) equally minus 28x plus forty
- 32x+101,2-14x=-28x+40
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Similar expressions
- 32x+10(1,2+14x)=-28x+40
- 32x-10(1,2-14x)=-28x+40
- 32x+10(1,2-14x)=-28x-40
- 32x+10(1,2-14x)=+28x+40
32x+10(1,2-14x)=-28x+40 equation
The teacher will be very surprised to see your correct solution 😉
The solution
You have entered
[src]
32*x + 10*(6/5 - 14*x) = -28*x + 40
$$32 x + 10 \left(\frac{6}{5} - 14 x\right) = 40 - 28 x$$
Detail solution
Given the linear equation:
Expand brackets in the left part
Move free summands (without x)
from left part to right part, we given:
$$- 108 x = 28 - 28 x$$
Move the summands with the unknown x
from the right part to the left part:
$$\left(-80\right) x = 28$$
Divide both parts of the equation by -80
We get the answer: x = -7/20
32*x+10*((6/5)-14*x) = -28*x+40
Expand brackets in the left part
32*x+10*6/5-14*x) = -28*x+40
Move free summands (without x)
from left part to right part, we given:
$$- 108 x = 28 - 28 x$$
Move the summands with the unknown x
from the right part to the left part:
$$\left(-80\right) x = 28$$
Divide both parts of the equation by -80
x = 28 / (-80)
We get the answer: x = -7/20
Sum and product of roots
[src]
sum
-7/20
$$- \frac{7}{20}$$
=
-7/20
$$- \frac{7}{20}$$
product
-7/20
$$- \frac{7}{20}$$
=
-7/20
$$- \frac{7}{20}$$
-7/20