Mister Exam
Other calculators
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How to use it?
- Equation:
-
Equation 9*(x-1)=x+15
-
Equation x^4=81
-
Equation (x-3)^2-(x+1)^2=12
-
Equation x^2+6x=0
- Express {x} in terms of y where:
- -19*x+10*y=-3
- 6*x+10*y=-7
- 8*x-18*y=16
- 17*x+14*y=-17
- 2x+y
- Plot:
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2x+y
- Canonical form:
- 2x+y
- Sum of series:
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20
- Integral of d{x}:
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20
- Limit of the function:
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20
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Identical expressions
- 2x+y= twenty
- 2x plus y equally 20
- 2x plus y equally twenty
-
Similar expressions
- 2x-y=20
- (x-y)*(x-y)*(2*(x-y)+2*(x+y))=2*(x^4-y^4)
2x+y=20 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the linear equation:
Looking for similar summands in the left part:
Move the summands with the other variables
from left part to right part, we given:
$$2 x = 20 - y$$
Divide both parts of the equation by 2
We get the answer: x = 10 - y/2
2*x+y = 20
Looking for similar summands in the left part:
y + 2*x = 20
Move the summands with the other variables
from left part to right part, we given:
$$2 x = 20 - y$$
Divide both parts of the equation by 2
x = 20 - y / (2)
We get the answer: x = 10 - y/2
The graph
Sum and product of roots
[src]
sum
re(y) I*im(y)
10 - ----- - -------
2 2
$$- \frac{\operatorname{re}{\left(y\right)}}{2} - \frac{i \operatorname{im}{\left(y\right)}}{2} + 10$$
=
re(y) I*im(y)
10 - ----- - -------
2 2
$$- \frac{\operatorname{re}{\left(y\right)}}{2} - \frac{i \operatorname{im}{\left(y\right)}}{2} + 10$$
product
re(y) I*im(y)
10 - ----- - -------
2 2
$$- \frac{\operatorname{re}{\left(y\right)}}{2} - \frac{i \operatorname{im}{\left(y\right)}}{2} + 10$$
=
re(y) I*im(y)
10 - ----- - -------
2 2
$$- \frac{\operatorname{re}{\left(y\right)}}{2} - \frac{i \operatorname{im}{\left(y\right)}}{2} + 10$$
10 - re(y)/2 - i*im(y)/2
Rapid solution
[src]
re(y) I*im(y)
x1 = 10 - ----- - -------
2 2
$$x_{1} = - \frac{\operatorname{re}{\left(y\right)}}{2} - \frac{i \operatorname{im}{\left(y\right)}}{2} + 10$$
x1 = -re(y)/2 - i*im(y)/2 + 10