2x-y=10 equation

The teacher will be very surprised to see your correct solution 😉

You have entered [src]

2*x - y = 10

$$2 x - y = 10$$

Simplify

Detail solution

Given the linear equation:

2*x-y = 10

Looking for similar summands in the left part:

-y + 2*x = 10

Move the summands with the other variables
from left part to right part, we given:
$$2 x = y + 10$$
Divide both parts of the equation by 2

x = 10 + y / (2)

We get the answer: x = 5 + y/2

The graph

Rapid solution [src]

         re(y)   I*im(y)
x1 = 5 + ----- + -------
           2        2

$$x_{1} = \frac{\operatorname{re}{\left(y\right)}}{2} + \frac{i \operatorname{im}{\left(y\right)}}{2} + 5$$

x1 = re(y)/2 + i*im(y)/2 + 5

Sum and product of roots [src]

sum

    re(y)   I*im(y)
5 + ----- + -------
      2        2

$$\frac{\operatorname{re}{\left(y\right)}}{2} + \frac{i \operatorname{im}{\left(y\right)}}{2} + 5$$

    re(y)   I*im(y)
5 + ----- + -------
      2        2

$$\frac{\operatorname{re}{\left(y\right)}}{2} + \frac{i \operatorname{im}{\left(y\right)}}{2} + 5$$

product

    re(y)   I*im(y)
5 + ----- + -------
      2        2

$$\frac{\operatorname{re}{\left(y\right)}}{2} + \frac{i \operatorname{im}{\left(y\right)}}{2} + 5$$

    re(y)   I*im(y)
5 + ----- + -------
      2        2

$$\frac{\operatorname{re}{\left(y\right)}}{2} + \frac{i \operatorname{im}{\left(y\right)}}{2} + 5$$

5 + re(y)/2 + i*im(y)/2