Mister Exam
Other calculators
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How to use it?
- Equation:
-
Equation (5*x+4)/2+3=9*x/4
-
Equation 2*x^2+18*x=0
-
Equation (x^2-9)^2+(x^2+x-6)^2=0
-
Equation cos(x-pi/2)=0
- Express {x} in terms of y where:
- -7*x-15*y=-6
- -17*x+7*y=0
- -10*x-17*y=-14
- -8*x-12*y=-7
- Graphing y =:
- 10x-2
-
Identical expressions
- 13x+ six =10x- two
- 13x plus 6 equally 10x minus 2
- 13x plus six equally 10x minus two
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Similar expressions
- 13x-6=10x-2
- 13x+6=10x+2
- 1*x^2-10*x-24=0
- 7*x^2+10*x-25=0
- 2*x^2-13*x+6=0
13x+6=10x-2 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the linear equation:
Move free summands (without x)
from left part to right part, we given:
$$13 x = 10 x - 8$$
Move the summands with the unknown x
from the right part to the left part:
$$3 x = -8$$
Divide both parts of the equation by 3
We get the answer: x = -8/3
13*x+6 = 10*x-2
Move free summands (without x)
from left part to right part, we given:
$$13 x = 10 x - 8$$
Move the summands with the unknown x
from the right part to the left part:
$$3 x = -8$$
Divide both parts of the equation by 3
x = -8 / (3)
We get the answer: x = -8/3
Sum and product of roots
[src]
sum
-8/3
$$- \frac{8}{3}$$
=
-8/3
$$- \frac{8}{3}$$
product
-8/3
$$- \frac{8}{3}$$
=
-8/3
$$- \frac{8}{3}$$
-8/3