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A simplest differential equations of 1order StepbyStep
How to use it?
Differential equation
:
Equation xydx(x+2y)^2dy=0
Equation y^2dx+(x^2+3xy+4y^2)dy=0
Equation d^2y/dx^23dy/dx+2y=0
Equation x^2(y'')+xy'+y=logx(sin(logx))
Identical expressions
xydx(x+2y)^2dy= zero
xydx minus (x plus 2y) squared dy equally 0
xydx minus (x plus 2y) squared dy equally zero
xydx(x+2y)2dy=0
xydxx+2y2dy=0
xydx(x+2y)²dy=0
xydx(x+2y) to the power of 2dy=0
xydxx+2y^2dy=0
xydx(x+2y)^2dy=O
Similar expressions
xydx+(x+2y)^2dy=0
xydx(x2y)^2dy=0
Differential equations
/
xydx(x+2y)^2dy=0
Differential equation xydx(x+2y)^2dy=0
The teacher will be very surprised to see your correct solution 😉
+ equation
Solve the differential equation!
v
For Cauchy problem:
y(
) =
y'(
) =
y''(
) =
y'''(
) =
y''''(
) =
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