z 2 ----------*(z - 2*pi*k) 1 - cos(z)
(z/(1 - cos(z)))*(z - 2*pi*k)^2
Apply the quotient rule, which is:
and .
To find :
Apply the product rule:
; to find :
Apply the power rule: goes to
; to find :
Let .
Apply the power rule: goes to
Then, apply the chain rule. Multiply by :
Differentiate term by term:
Apply the power rule: goes to
The derivative of the constant is zero.
The result is:
The result of the chain rule is:
The result is:
To find :
Differentiate term by term:
The derivative of the constant is zero.
The derivative of a constant times a function is the constant times the derivative of the function.
The derivative of cosine is negative sine:
So, the result is:
The result is:
Now plug in to the quotient rule:
Now simplify:
The answer is:
2 / 1 z*sin(z) \ z*(2*z - 4*pi*k) (z - 2*pi*k) *|---------- - -------------| + ---------------- |1 - cos(z) 2| 1 - cos(z) \ (1 - cos(z)) /
/ / 2 \\ 2 | | 2*sin (z) || (-z + 2*pi*k) *|2*sin(z) + z*|----------- + cos(z)|| / z*sin(z) \ \ \-1 + cos(z) // -2*z + 4*|1 + -----------|*(-z + 2*pi*k) - ---------------------------------------------------- \ -1 + cos(z)/ -1 + cos(z) ----------------------------------------------------------------------------------------------- -1 + cos(z)
/ 2 / 2 \ \ 2 | 6*sin (z) | 6*cos(z) 6*sin (z) | | / / 2 \\ (-z + 2*pi*k) *|3*cos(z) + ----------- + z*|-1 + ----------- + --------------|*sin(z)| | | 2*sin (z) || | -1 + cos(z) | -1 + cos(z) 2| | 6*(-z + 2*pi*k)*|2*sin(z) + z*|----------- + cos(z)|| \ \ (-1 + cos(z)) / / 6*z*sin(z) \ \-1 + cos(z) // -6 - -------------------------------------------------------------------------------------- - ----------- + ----------------------------------------------------- -1 + cos(z) -1 + cos(z) -1 + cos(z) ----------------------------------------------------------------------------------------------------------------------------------------------------------------- -1 + cos(z)