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y(x)=x^3cos(3x+1)

Derivative of y(x)=x^3cos(3x+1)

Function f() - derivative -N order at the point
v

The graph:

from to

Piecewise:

The solution

You have entered [src]
 3             
x *cos(3*x + 1)
$$x^{3} \cos{\left(3 x + 1 \right)}$$
d / 3             \
--\x *cos(3*x + 1)/
dx                 
$$\frac{d}{d x} x^{3} \cos{\left(3 x + 1 \right)}$$
Detail solution
  1. Apply the product rule:

    ; to find :

    1. Apply the power rule: goes to

    ; to find :

    1. Let .

    2. The derivative of cosine is negative sine:

    3. Then, apply the chain rule. Multiply by :

      1. Differentiate term by term:

        1. The derivative of a constant times a function is the constant times the derivative of the function.

          1. Apply the power rule: goes to

          So, the result is:

        2. The derivative of the constant is zero.

        The result is:

      The result of the chain rule is:

    The result is:

  2. Now simplify:


The answer is:

The graph
The first derivative [src]
     3                   2             
- 3*x *sin(3*x + 1) + 3*x *cos(3*x + 1)
$$- 3 x^{3} \sin{\left(3 x + 1 \right)} + 3 x^{2} \cos{\left(3 x + 1 \right)}$$
The second derivative [src]
    /                                       2             \
3*x*\2*cos(1 + 3*x) - 6*x*sin(1 + 3*x) - 3*x *cos(1 + 3*x)/
$$3 x \left(- 3 x^{2} \cos{\left(3 x + 1 \right)} - 6 x \sin{\left(3 x + 1 \right)} + 2 \cos{\left(3 x + 1 \right)}\right)$$
The third derivative [src]
  /                     2                                       3             \
3*\2*cos(1 + 3*x) - 27*x *cos(1 + 3*x) - 18*x*sin(1 + 3*x) + 9*x *sin(1 + 3*x)/
$$3 \cdot \left(9 x^{3} \sin{\left(3 x + 1 \right)} - 27 x^{2} \cos{\left(3 x + 1 \right)} - 18 x \sin{\left(3 x + 1 \right)} + 2 \cos{\left(3 x + 1 \right)}\right)$$
The graph
Derivative of y(x)=x^3cos(3x+1)