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y=x-ln(1+x^2)

Derivative of y=x-ln(1+x^2)

Function f() - derivative -N order at the point
v

The graph:

from to

Piecewise:

The solution

You have entered [src]
       /     2\
x - log\1 + x /
$$x - \log{\left(x^{2} + 1 \right)}$$
x - log(1 + x^2)
Detail solution
  1. Differentiate term by term:

    1. Apply the power rule: goes to

    2. The derivative of a constant times a function is the constant times the derivative of the function.

      1. Let .

      2. The derivative of is .

      3. Then, apply the chain rule. Multiply by :

        1. Differentiate term by term:

          1. The derivative of the constant is zero.

          2. Apply the power rule: goes to

          The result is:

        The result of the chain rule is:

      So, the result is:

    The result is:

  2. Now simplify:


The answer is:

The graph
The first derivative [src]
     2*x  
1 - ------
         2
    1 + x 
$$- \frac{2 x}{x^{2} + 1} + 1$$
The second derivative [src]
  /         2 \
  |      2*x  |
2*|-1 + ------|
  |          2|
  \     1 + x /
---------------
          2    
     1 + x     
$$\frac{2 \left(\frac{2 x^{2}}{x^{2} + 1} - 1\right)}{x^{2} + 1}$$
The third derivative [src]
    /        2 \
    |     4*x  |
4*x*|3 - ------|
    |         2|
    \    1 + x /
----------------
           2    
   /     2\     
   \1 + x /     
$$\frac{4 x \left(- \frac{4 x^{2}}{x^{2} + 1} + 3\right)}{\left(x^{2} + 1\right)^{2}}$$
The graph
Derivative of y=x-ln(1+x^2)