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y=(sqrt3x+1)-sin2x

Derivative of y=(sqrt3x+1)-sin2x

Function f() - derivative -N order at the point
v

The graph:

from to

Piecewise:

The solution

You have entered [src]
  _____               
\/ 3*x  + 1 - sin(2*x)
$$\left(\sqrt{3 x} + 1\right) - \sin{\left(2 x \right)}$$
sqrt(3*x) + 1 - sin(2*x)
Detail solution
  1. Differentiate term by term:

    1. Differentiate term by term:

      1. Let .

      2. Apply the power rule: goes to

      3. Then, apply the chain rule. Multiply by :

        1. The derivative of a constant times a function is the constant times the derivative of the function.

          1. Apply the power rule: goes to

          So, the result is:

        The result of the chain rule is:

      4. The derivative of the constant is zero.

      The result is:

    2. The derivative of a constant times a function is the constant times the derivative of the function.

      1. Let .

      2. The derivative of sine is cosine:

      3. Then, apply the chain rule. Multiply by :

        1. The derivative of a constant times a function is the constant times the derivative of the function.

          1. Apply the power rule: goes to

          So, the result is:

        The result of the chain rule is:

      So, the result is:

    The result is:


The answer is:

The graph
The first derivative [src]
                ___   ___
              \/ 3 *\/ x 
-2*cos(2*x) + -----------
                  2*x    
$$- 2 \cos{\left(2 x \right)} + \frac{\sqrt{3} \sqrt{x}}{2 x}$$
The second derivative [src]
               ___ 
             \/ 3  
4*sin(2*x) - ------
                3/2
             4*x   
$$4 \sin{\left(2 x \right)} - \frac{\sqrt{3}}{4 x^{\frac{3}{2}}}$$
The third derivative [src]
                 ___
             3*\/ 3 
8*cos(2*x) + -------
                 5/2
              8*x   
$$8 \cos{\left(2 x \right)} + \frac{3 \sqrt{3}}{8 x^{\frac{5}{2}}}$$
The graph
Derivative of y=(sqrt3x+1)-sin2x