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y=sinx^2+sin2x+sin2^2

Derivative of y=sinx^2+sin2x+sin2^2

Function f() - derivative -N order at the point
v

The graph:

from to

Piecewise:

The solution

You have entered [src]
   2                    2   
sin (x) + sin(2*x) + sin (2)
$$\left(\sin^{2}{\left(x \right)} + \sin{\left(2 x \right)}\right) + \sin^{2}{\left(2 \right)}$$
sin(x)^2 + sin(2*x) + sin(2)^2
Detail solution
  1. Differentiate term by term:

    1. Differentiate term by term:

      1. Let .

      2. Apply the power rule: goes to

      3. Then, apply the chain rule. Multiply by :

        1. The derivative of sine is cosine:

        The result of the chain rule is:

      4. Let .

      5. The derivative of sine is cosine:

      6. Then, apply the chain rule. Multiply by :

        1. The derivative of a constant times a function is the constant times the derivative of the function.

          1. Apply the power rule: goes to

          So, the result is:

        The result of the chain rule is:

      The result is:

    2. The derivative of the constant is zero.

    The result is:

  2. Now simplify:


The answer is:

The graph
The first derivative [src]
2*cos(2*x) + 2*cos(x)*sin(x)
$$2 \sin{\left(x \right)} \cos{\left(x \right)} + 2 \cos{\left(2 x \right)}$$
The second derivative [src]
  /   2         2                \
2*\cos (x) - sin (x) - 2*sin(2*x)/
$$2 \left(- \sin^{2}{\left(x \right)} - 2 \sin{\left(2 x \right)} + \cos^{2}{\left(x \right)}\right)$$
The third derivative [src]
-8*(cos(x)*sin(x) + cos(2*x))
$$- 8 \left(\sin{\left(x \right)} \cos{\left(x \right)} + \cos{\left(2 x \right)}\right)$$
The graph
Derivative of y=sinx^2+sin2x+sin2^2