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Derivative of y=sin^2(4x)+1/2cos8x

Function f() - derivative -N order at the point
v

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The solution

You have entered [src]
   2        cos(8*x)
sin (4*x) + --------
               2    
$$\sin^{2}{\left(4 x \right)} + \frac{\cos{\left(8 x \right)}}{2}$$
d /   2        cos(8*x)\
--|sin (4*x) + --------|
dx\               2    /
$$\frac{d}{d x} \left(\sin^{2}{\left(4 x \right)} + \frac{\cos{\left(8 x \right)}}{2}\right)$$
Detail solution
  1. Differentiate term by term:

    1. Let .

    2. Apply the power rule: goes to

    3. Then, apply the chain rule. Multiply by :

      1. Let .

      2. The derivative of sine is cosine:

      3. Then, apply the chain rule. Multiply by :

        1. The derivative of a constant times a function is the constant times the derivative of the function.

          1. Apply the power rule: goes to

          So, the result is:

        The result of the chain rule is:

      The result of the chain rule is:

    4. The derivative of a constant times a function is the constant times the derivative of the function.

      1. Let .

      2. The derivative of cosine is negative sine:

      3. Then, apply the chain rule. Multiply by :

        1. The derivative of a constant times a function is the constant times the derivative of the function.

          1. Apply the power rule: goes to

          So, the result is:

        The result of the chain rule is:

      So, the result is:

    The result is:

  2. Now simplify:


The answer is:

The first derivative [src]
-4*sin(8*x) + 8*cos(4*x)*sin(4*x)
$$8 \sin{\left(4 x \right)} \cos{\left(4 x \right)} - 4 \sin{\left(8 x \right)}$$
The second derivative [src]
   /   2           2                \
32*\cos (4*x) - sin (4*x) - cos(8*x)/
$$32 \left(- \sin^{2}{\left(4 x \right)} + \cos^{2}{\left(4 x \right)} - \cos{\left(8 x \right)}\right)$$
The third derivative [src]
256*(-2*cos(4*x)*sin(4*x) + sin(8*x))
$$256 \left(- 2 \sin{\left(4 x \right)} \cos{\left(4 x \right)} + \sin{\left(8 x \right)}\right)$$