Derivative of y=sin(5x-3x)

1. Let $u = - 3 x + 5 x$.

2. The derivative of sine is cosine:

   $$\frac{d}{d u} \sin{\left(u \right)} = \cos{\left(u \right)}$$

3. Then, apply the chain rule. Multiply by $\frac{d}{d x} \left(- 3 x + 5 x\right)$:

   1. Differentiate $- 3 x + 5 x$ term by term:

      1. The derivative of a constant times a function is the constant times the derivative of the function.

         1. Apply the power rule: $x$ goes to $1$

         So, the result is: $5$

      2. The derivative of a constant times a function is the constant times the derivative of the function.

         1. Apply the power rule: $x$ goes to $1$

         So, the result is: $-3$

      The result is: $2$

   The result of the chain rule is:

   $$2 \cos{\left(- 3 x + 5 x \right)}$$

4. Now simplify:

   $$2 \cos{\left(2 x \right)}$$

The answer is:

$$2 \cos{\left(2 x \right)}$$