Derivative of y=log(7^x)

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   / x\
log\7 /

$$\log{\left(7^{x} \right)}$$

log(7^x)

Detail solution

Let $u = 7^{x}$ .
The derivative of $\log{\left(u \right)}$ is $\frac{1}{u}$ .
Then, apply the chain rule. Multiply by $\frac{d}{d x} 7^{x}$ :
1. $\frac{d}{d x} 7^{x} = 7^{x} \log{\left(7 \right)}$
The result of the chain rule is:

$\log{\left(7 \right)}$

The answer is:

$\log{\left(7 \right)}$

The graph

Plot the graph f(x)

Plot the graph f'(x)

The first derivative [src]

log(7)

$$\log{\left(7 \right)}$$

Simplify

The second derivative [src]

$$0$$

Simplify

The third derivative [src]

$$0$$

Simplify

The graph