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y=ln(x+√4+x^2)

Derivative of y=ln(x+√4+x^2)

Function f() - derivative -N order at the point
v

The graph:

from to

Piecewise:

The solution

You have entered [src]
   /      ___    2\
log\x + \/ 4  + x /
$$\log{\left(x^{2} + x + \sqrt{4} \right)}$$
d /   /      ___    2\\
--\log\x + \/ 4  + x //
dx                     
$$\frac{d}{d x} \log{\left(x^{2} + x + \sqrt{4} \right)}$$
Detail solution
  1. Let .

  2. The derivative of is .

  3. Then, apply the chain rule. Multiply by :

    1. Differentiate term by term:

      1. Apply the power rule: goes to

      2. The derivative of the constant is zero.

      3. Apply the power rule: goes to

      The result is:

    The result of the chain rule is:

  4. Now simplify:


The answer is:

The graph
The first derivative [src]
   1 + 2*x    
--------------
      ___    2
x + \/ 4  + x 
$$\frac{2 x + 1}{x^{2} + x + \sqrt{4}}$$
The second derivative [src]
             2
    (1 + 2*x) 
2 - ----------
             2
    2 + x + x 
--------------
           2  
  2 + x + x   
$$\frac{- \frac{\left(2 x + 1\right)^{2}}{x^{2} + x + 2} + 2}{x^{2} + x + 2}$$
The third derivative [src]
            /              2\
            |     (1 + 2*x) |
2*(1 + 2*x)*|-3 + ----------|
            |              2|
            \     2 + x + x /
-----------------------------
                    2        
        /         2\         
        \2 + x + x /         
$$\frac{2 \cdot \left(2 x + 1\right) \left(\frac{\left(2 x + 1\right)^{2}}{x^{2} + x + 2} - 3\right)}{\left(x^{2} + x + 2\right)^{2}}$$
The graph
Derivative of y=ln(x+√4+x^2)