log(x) + 8*log(x)
Differentiate log(x)+8log(x)\log{\left(x \right)} + 8 \log{\left(x \right)}log(x)+8log(x) term by term:
The derivative of log(x)\log{\left(x \right)}log(x) is 1x\frac{1}{x}x1.
The derivative of a constant times a function is the constant times the derivative of the function.
So, the result is: 8x\frac{8}{x}x8
The result is: 9x\frac{9}{x}x9
The answer is:
9 - x
-9 --- 2 x
18 -- 3 x