Derivative of y=e^x-3+1

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 x        
e  - 3 + 1

$$e^{x} - 3 + 1$$

d / x        \
--\e  - 3 + 1/
dx

$$\frac{d}{d x} \left(e^{x} - 3 + 1\right)$$

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Detail solution

Differentiate $e^{x} - 3 + 1$ term by term:
1. The derivative of $e^{x}$ is itself.
2. The derivative of the constant $\left(-1\right) 3$ is zero.
3. The derivative of the constant $1$ is zero.
The result is: $e^{x}$

The answer is:

$e^{x}$

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The first derivative [src]

x
e

$$e^{x}$$

Simplify

The second derivative [src]

x
e

$$e^{x}$$

Simplify

The third derivative [src]

x
e

$$e^{x}$$

Simplify

The graph