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y=(e^(x-1))/(x-1)

Derivative of y=(e^(x-1))/(x-1)

Function f() - derivative -N order at the point
v

The graph:

from to

Piecewise:

The solution

You have entered [src]
 x - 1
E     
------
x - 1 
$$\frac{e^{x - 1}}{x - 1}$$
E^(x - 1)/(x - 1)
Detail solution
  1. Apply the quotient rule, which is:

    and .

    To find :

    1. Let .

    2. The derivative of is itself.

    3. Then, apply the chain rule. Multiply by :

      1. Differentiate term by term:

        1. Apply the power rule: goes to

        2. The derivative of the constant is zero.

        The result is:

      The result of the chain rule is:

    To find :

    1. Differentiate term by term:

      1. The derivative of the constant is zero.

      2. Apply the power rule: goes to

      The result is:

    Now plug in to the quotient rule:

  2. Now simplify:


The answer is:

The graph
The first derivative [src]
 x - 1     x - 1 
e         e      
------ - --------
x - 1           2
         (x - 1) 
$$\frac{e^{x - 1}}{x - 1} - \frac{e^{x - 1}}{\left(x - 1\right)^{2}}$$
The second derivative [src]
/      2          2    \  -1 + x
|1 - ------ + ---------|*e      
|    -1 + x           2|        
\             (-1 + x) /        
--------------------------------
             -1 + x             
$$\frac{\left(1 - \frac{2}{x - 1} + \frac{2}{\left(x - 1\right)^{2}}\right) e^{x - 1}}{x - 1}$$
The third derivative [src]
/        6         3          6    \  -1 + x
|1 - --------- - ------ + ---------|*e      
|            3   -1 + x           2|        
\    (-1 + x)             (-1 + x) /        
--------------------------------------------
                   -1 + x                   
$$\frac{\left(1 - \frac{3}{x - 1} + \frac{6}{\left(x - 1\right)^{2}} - \frac{6}{\left(x - 1\right)^{3}}\right) e^{x - 1}}{x - 1}$$
The graph
Derivative of y=(e^(x-1))/(x-1)