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y=e^(2x-3)/(x+5)

Derivative of y=e^(2x-3)/(x+5)

Function f() - derivative -N order at the point
v

The graph:

from to

Piecewise:

The solution

You have entered [src]
 2*x - 3
E       
--------
 x + 5  
$$\frac{e^{2 x - 3}}{x + 5}$$
E^(2*x - 3)/(x + 5)
Detail solution
  1. Apply the quotient rule, which is:

    and .

    To find :

    1. Let .

    2. The derivative of is itself.

    3. Then, apply the chain rule. Multiply by :

      1. Differentiate term by term:

        1. The derivative of a constant times a function is the constant times the derivative of the function.

          1. Apply the power rule: goes to

          So, the result is:

        2. The derivative of the constant is zero.

        The result is:

      The result of the chain rule is:

    To find :

    1. Differentiate term by term:

      1. The derivative of the constant is zero.

      2. Apply the power rule: goes to

      The result is:

    Now plug in to the quotient rule:

  2. Now simplify:


The answer is:

The graph
The first derivative [src]
   2*x - 3      2*x - 3
  e          2*e       
- -------- + ----------
         2     x + 5   
  (x + 5)              
$$\frac{2 e^{2 x - 3}}{x + 5} - \frac{e^{2 x - 3}}{\left(x + 5\right)^{2}}$$
The second derivative [src]
  /       1         2  \  -3 + 2*x
2*|2 + -------- - -----|*e        
  |           2   5 + x|          
  \    (5 + x)         /          
----------------------------------
              5 + x               
$$\frac{2 \left(2 - \frac{2}{x + 5} + \frac{1}{\left(x + 5\right)^{2}}\right) e^{2 x - 3}}{x + 5}$$
The third derivative [src]
  /      6        3          6    \  -3 + 2*x
2*|4 - ----- - -------- + --------|*e        
  |    5 + x          3          2|          
  \            (5 + x)    (5 + x) /          
---------------------------------------------
                    5 + x                    
$$\frac{2 \left(4 - \frac{6}{x + 5} + \frac{6}{\left(x + 5\right)^{2}} - \frac{3}{\left(x + 5\right)^{3}}\right) e^{2 x - 3}}{x + 5}$$
The graph
Derivative of y=e^(2x-3)/(x+5)