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Derivative of (x^2+x-1)/(x+2)

Function f() - derivative -N order at the point
v

The graph:

from to

Piecewise:

The solution

You have entered [src]
 2        
x  + x - 1
----------
  x + 2   
$$\frac{\left(x^{2} + x\right) - 1}{x + 2}$$
(x^2 + x - 1)/(x + 2)
Detail solution
  1. Apply the quotient rule, which is:

    and .

    To find :

    1. Differentiate term by term:

      1. The derivative of the constant is zero.

      2. Apply the power rule: goes to

      3. Apply the power rule: goes to

      The result is:

    To find :

    1. Differentiate term by term:

      1. The derivative of the constant is zero.

      2. Apply the power rule: goes to

      The result is:

    Now plug in to the quotient rule:

  2. Now simplify:


The answer is:

The graph
The first derivative [src]
           2        
1 + 2*x   x  + x - 1
------- - ----------
 x + 2            2 
           (x + 2)  
$$\frac{2 x + 1}{x + 2} - \frac{\left(x^{2} + x\right) - 1}{\left(x + 2\right)^{2}}$$
The second derivative [src]
  /              2          \
  |    -1 + x + x    1 + 2*x|
2*|1 + ----------- - -------|
  |             2     2 + x |
  \      (2 + x)            /
-----------------------------
            2 + x            
$$\frac{2 \left(1 - \frac{2 x + 1}{x + 2} + \frac{x^{2} + x - 1}{\left(x + 2\right)^{2}}\right)}{x + 2}$$
The third derivative [src]
  /                         2\
  |     1 + 2*x   -1 + x + x |
6*|-1 + ------- - -----------|
  |      2 + x             2 |
  \                 (2 + x)  /
------------------------------
                  2           
           (2 + x)            
$$\frac{6 \left(-1 + \frac{2 x + 1}{x + 2} - \frac{x^{2} + x - 1}{\left(x + 2\right)^{2}}\right)}{\left(x + 2\right)^{2}}$$