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Derivative of (x^2-2*x+1)/(x+2)

Function f() - derivative -N order at the point
v

The graph:

from to

Piecewise:

The solution

You have entered [src]
 2          
x  - 2*x + 1
------------
   x + 2    
$$\frac{\left(x^{2} - 2 x\right) + 1}{x + 2}$$
(x^2 - 2*x + 1)/(x + 2)
Detail solution
  1. Apply the quotient rule, which is:

    and .

    To find :

    1. Differentiate term by term:

      1. The derivative of the constant is zero.

      2. Apply the power rule: goes to

      3. The derivative of a constant times a function is the constant times the derivative of the function.

        1. Apply the power rule: goes to

        So, the result is:

      The result is:

    To find :

    1. Differentiate term by term:

      1. The derivative of the constant is zero.

      2. Apply the power rule: goes to

      The result is:

    Now plug in to the quotient rule:

  2. Now simplify:


The answer is:

The graph
The first derivative [src]
            2          
-2 + 2*x   x  - 2*x + 1
-------- - ------------
 x + 2              2  
             (x + 2)   
$$\frac{2 x - 2}{x + 2} - \frac{\left(x^{2} - 2 x\right) + 1}{\left(x + 2\right)^{2}}$$
The second derivative [src]
  /         2                   \
  |    1 + x  - 2*x   2*(-1 + x)|
2*|1 + ------------ - ----------|
  |             2       2 + x   |
  \      (2 + x)                /
---------------------------------
              2 + x              
$$\frac{2 \left(- \frac{2 \left(x - 1\right)}{x + 2} + 1 + \frac{x^{2} - 2 x + 1}{\left(x + 2\right)^{2}}\right)}{x + 2}$$
The third derivative [src]
  /          2                   \
  |     1 + x  - 2*x   2*(-1 + x)|
6*|-1 - ------------ + ----------|
  |              2       2 + x   |
  \       (2 + x)                /
----------------------------------
                    2             
             (2 + x)              
$$\frac{6 \left(\frac{2 \left(x - 1\right)}{x + 2} - 1 - \frac{x^{2} - 2 x + 1}{\left(x + 2\right)^{2}}\right)}{\left(x + 2\right)^{2}}$$