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(x^2-8*x)/(x+1)

Derivative of (x^2-8*x)/(x+1)

Function f() - derivative -N order at the point
v

The graph:

from to

Piecewise:

The solution

You have entered [src]
 2      
x  - 8*x
--------
 x + 1  
$$\frac{x^{2} - 8 x}{x + 1}$$
(x^2 - 8*x)/(x + 1)
Detail solution
  1. Apply the quotient rule, which is:

    and .

    To find :

    1. Differentiate term by term:

      1. Apply the power rule: goes to

      2. The derivative of a constant times a function is the constant times the derivative of the function.

        1. Apply the power rule: goes to

        So, the result is:

      The result is:

    To find :

    1. Differentiate term by term:

      1. The derivative of the constant is zero.

      2. Apply the power rule: goes to

      The result is:

    Now plug in to the quotient rule:

  2. Now simplify:


The answer is:

The graph
The first derivative [src]
            2      
-8 + 2*x   x  - 8*x
-------- - --------
 x + 1            2
           (x + 1) 
$$\frac{2 x - 8}{x + 1} - \frac{x^{2} - 8 x}{\left(x + 1\right)^{2}}$$
The second derivative [src]
  /    2*(-4 + x)   x*(-8 + x)\
2*|1 - ---------- + ----------|
  |      1 + x              2 |
  \                  (1 + x)  /
-------------------------------
             1 + x             
$$\frac{2 \left(\frac{x \left(x - 8\right)}{\left(x + 1\right)^{2}} - \frac{2 \left(x - 4\right)}{x + 1} + 1\right)}{x + 1}$$
The third derivative [src]
  /     2*(-4 + x)   x*(-8 + x)\
6*|-1 + ---------- - ----------|
  |       1 + x              2 |
  \                   (1 + x)  /
--------------------------------
                   2            
            (1 + x)             
$$\frac{6 \left(- \frac{x \left(x - 8\right)}{\left(x + 1\right)^{2}} + \frac{2 \left(x - 4\right)}{x + 1} - 1\right)}{\left(x + 1\right)^{2}}$$
The graph
Derivative of (x^2-8*x)/(x+1)