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(x^3+4)/(x^2)

Derivative of (x^3+4)/(x^2)

Function f() - derivative -N order at the point
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The graph:

from to

Piecewise:

The solution

You have entered [src]
 3    
x  + 4
------
   2  
  x   
x3+4x2\frac{x^{3} + 4}{x^{2}}
  / 3    \
d |x  + 4|
--|------|
dx|   2  |
  \  x   /
ddxx3+4x2\frac{d}{d x} \frac{x^{3} + 4}{x^{2}}
Detail solution
  1. Apply the quotient rule, which is:

    ddxf(x)g(x)=f(x)ddxg(x)+g(x)ddxf(x)g2(x)\frac{d}{d x} \frac{f{\left(x \right)}}{g{\left(x \right)}} = \frac{- f{\left(x \right)} \frac{d}{d x} g{\left(x \right)} + g{\left(x \right)} \frac{d}{d x} f{\left(x \right)}}{g^{2}{\left(x \right)}}

    f(x)=x3+4f{\left(x \right)} = x^{3} + 4 and g(x)=x2g{\left(x \right)} = x^{2}.

    To find ddxf(x)\frac{d}{d x} f{\left(x \right)}:

    1. Differentiate x3+4x^{3} + 4 term by term:

      1. The derivative of the constant 44 is zero.

      2. Apply the power rule: x3x^{3} goes to 3x23 x^{2}

      The result is: 3x23 x^{2}

    To find ddxg(x)\frac{d}{d x} g{\left(x \right)}:

    1. Apply the power rule: x2x^{2} goes to 2x2 x

    Now plug in to the quotient rule:

    3x42x(x3+4)x4\frac{3 x^{4} - 2 x \left(x^{3} + 4\right)}{x^{4}}

  2. Now simplify:

    18x31 - \frac{8}{x^{3}}


The answer is:

18x31 - \frac{8}{x^{3}}

The graph
02468-8-6-4-2-1010-2000020000
The first derivative [src]
    / 3    \      2
  2*\x  + 4/   3*x 
- ---------- + ----
       3         2 
      x         x  
3x2x22(x3+4)x3\frac{3 x^{2}}{x^{2}} - \frac{2 \left(x^{3} + 4\right)}{x^{3}}
The second derivative [src]
  /          3\
  |     4 + x |
6*|-1 + ------|
  |        3  |
  \       x   /
---------------
       x       
6(1+x3+4x3)x\frac{6 \left(-1 + \frac{x^{3} + 4}{x^{3}}\right)}{x}
The third derivative [src]
   /         3\
   |    4 + x |
24*|1 - ------|
   |       3  |
   \      x   /
---------------
        2      
       x       
24(1x3+4x3)x2\frac{24 \cdot \left(1 - \frac{x^{3} + 4}{x^{3}}\right)}{x^{2}}
The graph
Derivative of (x^3+4)/(x^2)