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Derivative of (x^3-1)/(x+2)

Function f() - derivative -N order at the point
v

The graph:

from to

Piecewise:

The solution

You have entered [src]
 3    
x  - 1
------
x + 2 
$$\frac{x^{3} - 1}{x + 2}$$
(x^3 - 1)/(x + 2)
Detail solution
  1. Apply the quotient rule, which is:

    and .

    To find :

    1. Differentiate term by term:

      1. The derivative of the constant is zero.

      2. Apply the power rule: goes to

      The result is:

    To find :

    1. Differentiate term by term:

      1. The derivative of the constant is zero.

      2. Apply the power rule: goes to

      The result is:

    Now plug in to the quotient rule:


The answer is:

The graph
The first derivative [src]
    3            2
   x  - 1     3*x 
- -------- + -----
         2   x + 2
  (x + 2)         
$$\frac{3 x^{2}}{x + 2} - \frac{x^{3} - 1}{\left(x + 2\right)^{2}}$$
The second derivative [src]
  /            3        2\
  |      -1 + x      3*x |
2*|3*x + -------- - -----|
  |             2   2 + x|
  \      (2 + x)         /
--------------------------
          2 + x           
$$\frac{2 \left(- \frac{3 x^{2}}{x + 2} + 3 x + \frac{x^{3} - 1}{\left(x + 2\right)^{2}}\right)}{x + 2}$$
The third derivative [src]
  /          3                 2  \
  |    -1 + x      3*x      3*x   |
6*|1 - -------- - ----- + --------|
  |           3   2 + x          2|
  \    (2 + x)            (2 + x) /
-----------------------------------
               2 + x               
$$\frac{6 \left(\frac{3 x^{2}}{\left(x + 2\right)^{2}} - \frac{3 x}{x + 2} + 1 - \frac{x^{3} - 1}{\left(x + 2\right)^{3}}\right)}{x + 2}$$