Mister Exam

Derivative of x^2ln2x

Function f() - derivative -N order at the point
v

The graph:

from to

Piecewise:

The solution

You have entered [src]
 2         
x *log(2*x)
x2log(2x)x^{2} \log{\left(2 x \right)}
d / 2         \
--\x *log(2*x)/
dx             
ddxx2log(2x)\frac{d}{d x} x^{2} \log{\left(2 x \right)}
Detail solution
  1. Apply the product rule:

    ddxf(x)g(x)=f(x)ddxg(x)+g(x)ddxf(x)\frac{d}{d x} f{\left(x \right)} g{\left(x \right)} = f{\left(x \right)} \frac{d}{d x} g{\left(x \right)} + g{\left(x \right)} \frac{d}{d x} f{\left(x \right)}

    f(x)=x2f{\left(x \right)} = x^{2}; to find ddxf(x)\frac{d}{d x} f{\left(x \right)}:

    1. Apply the power rule: x2x^{2} goes to 2x2 x

    g(x)=log(2x)g{\left(x \right)} = \log{\left(2 x \right)}; to find ddxg(x)\frac{d}{d x} g{\left(x \right)}:

    1. Let u=2xu = 2 x.

    2. The derivative of log(u)\log{\left(u \right)} is 1u\frac{1}{u}.

    3. Then, apply the chain rule. Multiply by ddx2x\frac{d}{d x} 2 x:

      1. The derivative of a constant times a function is the constant times the derivative of the function.

        1. Apply the power rule: xx goes to 11

        So, the result is: 22

      The result of the chain rule is:

      1x\frac{1}{x}

    The result is: 2xlog(2x)+x2 x \log{\left(2 x \right)} + x

  2. Now simplify:

    x(2log(2x)+1)x \left(2 \log{\left(2 x \right)} + 1\right)


The answer is:

x(2log(2x)+1)x \left(2 \log{\left(2 x \right)} + 1\right)

The graph
02468-8-6-4-2-1010-500500
The first derivative [src]
x + 2*x*log(2*x)
2xlog(2x)+x2 x \log{\left(2 x \right)} + x
The second derivative [src]
3 + 2*log(2*x)
2log(2x)+32 \log{\left(2 x \right)} + 3
The third derivative [src]
2
-
x
2x\frac{2}{x}
The graph
Derivative of x^2ln2x