Mister Exam

Derivative of x*e^(3x)

Function f() - derivative -N order at the point
v

The graph:

from to

Piecewise:

The solution

You have entered [src]
   3*x
x*e   
xe3xx e^{3 x}
d /   3*x\
--\x*e   /
dx        
ddxxe3x\frac{d}{d x} x e^{3 x}
Detail solution
  1. Apply the product rule:

    ddxf(x)g(x)=f(x)ddxg(x)+g(x)ddxf(x)\frac{d}{d x} f{\left(x \right)} g{\left(x \right)} = f{\left(x \right)} \frac{d}{d x} g{\left(x \right)} + g{\left(x \right)} \frac{d}{d x} f{\left(x \right)}

    f(x)=xf{\left(x \right)} = x; to find ddxf(x)\frac{d}{d x} f{\left(x \right)}:

    1. Apply the power rule: xx goes to 11

    g(x)=e3xg{\left(x \right)} = e^{3 x}; to find ddxg(x)\frac{d}{d x} g{\left(x \right)}:

    1. Let u=3xu = 3 x.

    2. The derivative of eue^{u} is itself.

    3. Then, apply the chain rule. Multiply by ddx3x\frac{d}{d x} 3 x:

      1. The derivative of a constant times a function is the constant times the derivative of the function.

        1. Apply the power rule: xx goes to 11

        So, the result is: 33

      The result of the chain rule is:

      3e3x3 e^{3 x}

    The result is: 3xe3x+e3x3 x e^{3 x} + e^{3 x}

  2. Now simplify:

    (3x+1)e3x\left(3 x + 1\right) e^{3 x}


The answer is:

(3x+1)e3x\left(3 x + 1\right) e^{3 x}

The graph
02468-8-6-4-2-1010-500000000000000500000000000000
The first derivative [src]
 3*x        3*x
e    + 3*x*e   
3xe3x+e3x3 x e^{3 x} + e^{3 x}
The second derivative [src]
             3*x
3*(2 + 3*x)*e   
3(3x+2)e3x3 \cdot \left(3 x + 2\right) e^{3 x}
The third derivative [src]
            3*x
27*(1 + x)*e   
27(x+1)e3x27 \left(x + 1\right) e^{3 x}
The graph
Derivative of x*e^(3x)