x - 1 ------------ /log(x - 1)\ |----------| \ x - 1 /
(x - 1)/((log(x - 1)/(x - 1)))
Apply the quotient rule, which is:
and .
To find :
Let .
Apply the power rule: goes to
Then, apply the chain rule. Multiply by :
Differentiate term by term:
The derivative of the constant is zero.
Apply the power rule: goes to
The result is:
The result of the chain rule is:
To find :
Let .
The derivative of is .
Then, apply the chain rule. Multiply by :
Differentiate term by term:
Apply the power rule: goes to
The derivative of the constant is zero.
The result is:
The result of the chain rule is:
Now plug in to the quotient rule:
Now simplify:
The answer is:
3 / 1 log(x - 1)\ (x - 1) *|- -------- + ----------| | 2 2 | 1 \ (x - 1) (x - 1) / ------------ + ---------------------------------- /log(x - 1)\ 2 |----------| log (x - 1) \ x - 1 /
/ 1 \ -1 + log(-1 + x) |1 - -----------|*(-1 + log(-1 + x)) - ---------------- + log(-1 + x) \ log(-1 + x)/ log(-1 + x) --------------------------------------------------------------------- 2 log (-1 + x)
/ 1 \ / 2 \ |1 - -----------|*(-1 + log(-1 + x)) |1 - -----------|*(-1 + log(-1 + x)) / 1 \ 6*(-1 + log(-1 + x)) 3*(-3 + 2*log(-1 + x)) 3*(-1 + log(-1 + x)) / 1 \ \ log(-1 + x)/ \ log(-1 + x)/ 3 - 2*log(-1 + x) - |1 - -----------|*(-3 + 2*log(-1 + x)) - -------------------- + ---------------------- + -------------------- + 4*|1 - -----------|*(-1 + log(-1 + x)) - ------------------------------------ - ------------------------------------ \ log(-1 + x)/ log(-1 + x) log(-1 + x) 2 \ log(-1 + x)/ log(-1 + x) log(-1 + x) log (-1 + x) -------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------- 2 (-1 + x)*log (-1 + x)