x x 2 + E
2^x + E^x
Differentiate 2x+ex2^{x} + e^{x}2x+ex term by term:
ddx2x=2xlog(2)\frac{d}{d x} 2^{x} = 2^{x} \log{\left(2 \right)}dxd2x=2xlog(2)
The derivative of exe^{x}ex is itself.
The result is: 2xlog(2)+ex2^{x} \log{\left(2 \right)} + e^{x}2xlog(2)+ex
The answer is:
x x E + 2 *log(2)
x 2 x 2 *log (2) + e
x 3 x 2 *log (2) + e