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Derivative of 2*x*sin(2*x)-1

Function f() - derivative -N order at the point
v

The graph:

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The solution

You have entered [src]
2*x*sin(2*x) - 1
$$2 x \sin{\left(2 x \right)} - 1$$
(2*x)*sin(2*x) - 1
Detail solution
  1. Differentiate term by term:

    1. Apply the product rule:

      ; to find :

      1. The derivative of a constant times a function is the constant times the derivative of the function.

        1. Apply the power rule: goes to

        So, the result is:

      ; to find :

      1. Let .

      2. The derivative of sine is cosine:

      3. Then, apply the chain rule. Multiply by :

        1. The derivative of a constant times a function is the constant times the derivative of the function.

          1. Apply the power rule: goes to

          So, the result is:

        The result of the chain rule is:

      The result is:

    2. The derivative of the constant is zero.

    The result is:


The answer is:

The graph
The first derivative [src]
2*sin(2*x) + 4*x*cos(2*x)
$$4 x \cos{\left(2 x \right)} + 2 \sin{\left(2 x \right)}$$
The second derivative [src]
8*(-x*sin(2*x) + cos(2*x))
$$8 \left(- x \sin{\left(2 x \right)} + \cos{\left(2 x \right)}\right)$$
The third derivative [src]
-8*(3*sin(2*x) + 2*x*cos(2*x))
$$- 8 \left(2 x \cos{\left(2 x \right)} + 3 \sin{\left(2 x \right)}\right)$$