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Derivative of 2*sin(x-pi/3)*cos(x-pi/3)

Function f() - derivative -N order at the point
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The solution

You have entered [src]
     /    pi\    /    pi\
2*sin|x - --|*cos|x - --|
     \    3 /    \    3 /
$$2 \sin{\left(x - \frac{\pi}{3} \right)} \cos{\left(x - \frac{\pi}{3} \right)}$$
(2*sin(x - pi/3))*cos(x - pi/3)
Detail solution
  1. Apply the product rule:

    ; to find :

    1. The derivative of a constant times a function is the constant times the derivative of the function.

      1. Let .

      2. The derivative of sine is cosine:

      3. Then, apply the chain rule. Multiply by :

        1. Differentiate term by term:

          1. Apply the power rule: goes to

          2. The derivative of the constant is zero.

          The result is:

        The result of the chain rule is:

      So, the result is:

    ; to find :

    1. Let .

    2. The derivative of cosine is negative sine:

    3. Then, apply the chain rule. Multiply by :

      1. Differentiate term by term:

        1. Apply the power rule: goes to

        2. The derivative of the constant is zero.

        The result is:

      The result of the chain rule is:

    The result is:

  2. Now simplify:


The answer is:

The graph
The first derivative [src]
       2/    pi\        2/    pi\
- 2*sin |x - --| + 2*cos |x - --|
        \    3 /         \    3 /
$$- 2 \sin^{2}{\left(x - \frac{\pi}{3} \right)} + 2 \cos^{2}{\left(x - \frac{\pi}{3} \right)}$$
The second derivative [src]
     /    pi\    /    pi\
8*cos|x + --|*sin|x + --|
     \    6 /    \    6 /
$$8 \sin{\left(x + \frac{\pi}{6} \right)} \cos{\left(x + \frac{\pi}{6} \right)}$$
The third derivative [src]
  /   2/    pi\      2/    pi\\
8*|cos |x + --| - sin |x + --||
  \    \    6 /       \    6 //
$$8 \left(- \sin^{2}{\left(x + \frac{\pi}{6} \right)} + \cos^{2}{\left(x + \frac{\pi}{6} \right)}\right)$$