Mister Exam

Derivative of 2cos(y)^2

Function f() - derivative -N order at the point
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The graph:

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Piecewise:

The solution

You have entered [src]
     2   
2*cos (y)
2cos2(y)2 \cos^{2}{\left(y \right)}
2*cos(y)^2
Detail solution
  1. The derivative of a constant times a function is the constant times the derivative of the function.

    1. Let u=cos(y)u = \cos{\left(y \right)}.

    2. Apply the power rule: u2u^{2} goes to 2u2 u

    3. Then, apply the chain rule. Multiply by ddycos(y)\frac{d}{d y} \cos{\left(y \right)}:

      1. The derivative of cosine is negative sine:

        ddycos(y)=sin(y)\frac{d}{d y} \cos{\left(y \right)} = - \sin{\left(y \right)}

      The result of the chain rule is:

      2sin(y)cos(y)- 2 \sin{\left(y \right)} \cos{\left(y \right)}

    So, the result is: 4sin(y)cos(y)- 4 \sin{\left(y \right)} \cos{\left(y \right)}

  2. Now simplify:

    2sin(2y)- 2 \sin{\left(2 y \right)}


The answer is:

2sin(2y)- 2 \sin{\left(2 y \right)}

The graph
02468-8-6-4-2-10105-5
The first derivative [src]
-4*cos(y)*sin(y)
4sin(y)cos(y)- 4 \sin{\left(y \right)} \cos{\left(y \right)}
The second derivative [src]
  /   2         2   \
4*\sin (y) - cos (y)/
4(sin2(y)cos2(y))4 \left(\sin^{2}{\left(y \right)} - \cos^{2}{\left(y \right)}\right)
The third derivative [src]
16*cos(y)*sin(y)
16sin(y)cos(y)16 \sin{\left(y \right)} \cos{\left(y \right)}