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Derivative of 2(a*cos2t+sin2t)

Function f() - derivative -N order at the point
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The solution

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2*(a*cos(2*t) + sin(2*t))
$$2 \left(a \cos{\left(2 t \right)} + \sin{\left(2 t \right)}\right)$$
2*(a*cos(2*t) + sin(2*t))
Detail solution
  1. The derivative of a constant times a function is the constant times the derivative of the function.

    1. Differentiate term by term:

      1. The derivative of a constant times a function is the constant times the derivative of the function.

        1. Let .

        2. The derivative of cosine is negative sine:

        3. Then, apply the chain rule. Multiply by :

          1. The derivative of a constant times a function is the constant times the derivative of the function.

            1. Apply the power rule: goes to

            So, the result is:

          The result of the chain rule is:

        So, the result is:

      2. Let .

      3. The derivative of sine is cosine:

      4. Then, apply the chain rule. Multiply by :

        1. The derivative of a constant times a function is the constant times the derivative of the function.

          1. Apply the power rule: goes to

          So, the result is:

        The result of the chain rule is:

      The result is:

    So, the result is:


The answer is:

The first derivative [src]
4*cos(2*t) - 4*a*sin(2*t)
$$- 4 a \sin{\left(2 t \right)} + 4 \cos{\left(2 t \right)}$$
The second derivative [src]
-8*(a*cos(2*t) + sin(2*t))
$$- 8 \left(a \cos{\left(2 t \right)} + \sin{\left(2 t \right)}\right)$$
The third derivative [src]
16*(-cos(2*t) + a*sin(2*t))
$$16 \left(a \sin{\left(2 t \right)} - \cos{\left(2 t \right)}\right)$$