Derivative of 3x-ln(x+3)^3

1. Differentiate $3 x - \log{\left(x + 3 \right)}^{3}$ term by term:

   1. The derivative of a constant times a function is the constant times the derivative of the function.

      1. Apply the power rule: $x$ goes to $1$

      So, the result is: $3$

   2. The derivative of a constant times a function is the constant times the derivative of the function.

      1. Let $u = \log{\left(x + 3 \right)}$.

      2. Apply the power rule: $u^{3}$ goes to $3 u^{2}$

      3. Then, apply the chain rule. Multiply by $\frac{d}{d x} \log{\left(x + 3 \right)}$:

         1. Let $u = x + 3$.

         2. The derivative of $\log{\left(u \right)}$ is $\frac{1}{u}$.

         3. Then, apply the chain rule. Multiply by $\frac{d}{d x} \left(x + 3\right)$:

            1. Differentiate $x + 3$ term by term:

               1. Apply the power rule: $x$ goes to $1$

               2. The derivative of the constant $3$ is zero.

               The result is: $1$

            The result of the chain rule is:

            $$\frac{1}{x + 3}$$

         The result of the chain rule is:

         $$\frac{3 \log{\left(x + 3 \right)}^{2}}{x + 3}$$

      So, the result is: $- \frac{3 \log{\left(x + 3 \right)}^{2}}{x + 3}$

   The result is: $3 - \frac{3 \log{\left(x + 3 \right)}^{2}}{x + 3}$

2. Now simplify:

   $$\frac{3 \left(x - \log{\left(x + 3 \right)}^{2} + 3\right)}{x + 3}$$

The answer is: