Mister Exam

Derivative of 3*sin(t)-sin(3t)

Function f() - derivative -N order at the point
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The graph:

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Piecewise:

The solution

You have entered [src]
3*sin(t) - sin(3*t)
3sin(t)sin(3t)3 \sin{\left(t \right)} - \sin{\left(3 t \right)}
3*sin(t) - sin(3*t)
Detail solution
  1. Differentiate 3sin(t)sin(3t)3 \sin{\left(t \right)} - \sin{\left(3 t \right)} term by term:

    1. The derivative of a constant times a function is the constant times the derivative of the function.

      1. The derivative of sine is cosine:

        ddtsin(t)=cos(t)\frac{d}{d t} \sin{\left(t \right)} = \cos{\left(t \right)}

      So, the result is: 3cos(t)3 \cos{\left(t \right)}

    2. The derivative of a constant times a function is the constant times the derivative of the function.

      1. Let u=3tu = 3 t.

      2. The derivative of sine is cosine:

        ddusin(u)=cos(u)\frac{d}{d u} \sin{\left(u \right)} = \cos{\left(u \right)}

      3. Then, apply the chain rule. Multiply by ddt3t\frac{d}{d t} 3 t:

        1. The derivative of a constant times a function is the constant times the derivative of the function.

          1. Apply the power rule: tt goes to 11

          So, the result is: 33

        The result of the chain rule is:

        3cos(3t)3 \cos{\left(3 t \right)}

      So, the result is: 3cos(3t)- 3 \cos{\left(3 t \right)}

    The result is: 3cos(t)3cos(3t)3 \cos{\left(t \right)} - 3 \cos{\left(3 t \right)}


The answer is:

3cos(t)3cos(3t)3 \cos{\left(t \right)} - 3 \cos{\left(3 t \right)}

The graph
02468-8-6-4-2-1010-1010
The first derivative [src]
-3*cos(3*t) + 3*cos(t)
3cos(t)3cos(3t)3 \cos{\left(t \right)} - 3 \cos{\left(3 t \right)}
The second derivative [src]
3*(-sin(t) + 3*sin(3*t))
3(sin(t)+3sin(3t))3 \left(- \sin{\left(t \right)} + 3 \sin{\left(3 t \right)}\right)
The third derivative [src]
3*(-cos(t) + 9*cos(3*t))
3(cos(t)+9cos(3t))3 \left(- \cos{\left(t \right)} + 9 \cos{\left(3 t \right)}\right)