Derivative of tan^-1x

The solution

You have entered [src]

  1   
------
tan(x)

$$\frac{1}{\tan{\left(x \right)}}$$

1/tan(x)

Detail solution

Let $u = \tan{\left(x \right)}$ .
Apply the power rule: $\frac{1}{u}$ goes to $- \frac{1}{u^{2}}$
Then, apply the chain rule. Multiply by $\frac{d}{d x} \tan{\left(x \right)}$ :
1. Rewrite the function to be differentiated:
  
  $\tan{\left(x \right)} = \frac{\sin{\left(x \right)}}{\cos{\left(x \right)}}$
2. Apply the quotient rule, which is:
  
  $\frac{d}{d x} \frac{f{\left(x \right)}}{g{\left(x \right)}} = \frac{- f{\left(x \right)} \frac{d}{d x} g{\left(x \right)} + g{\left(x \right)} \frac{d}{d x} f{\left(x \right)}}{g^{2}{\left(x \right)}}$
  
  $f{\left(x \right)} = \sin{\left(x \right)}$ and $g{\left(x \right)} = \cos{\left(x \right)}$ .
  
  To find $\frac{d}{d x} f{\left(x \right)}$ :
  1. The derivative of sine is cosine:
    
    $\frac{d}{d x} \sin{\left(x \right)} = \cos{\left(x \right)}$
  To find $\frac{d}{d x} g{\left(x \right)}$ :
  1. The derivative of cosine is negative sine:
    
    $\frac{d}{d x} \cos{\left(x \right)} = - \sin{\left(x \right)}$
  Now plug in to the quotient rule:
  
  $\frac{\sin^{2}{\left(x \right)} + \cos^{2}{\left(x \right)}}{\cos^{2}{\left(x \right)}}$
The result of the chain rule is:

$- \frac{\sin^{2}{\left(x \right)} + \cos^{2}{\left(x \right)}}{\cos^{2}{\left(x \right)} \tan^{2}{\left(x \right)}}$
Now simplify:

$- \frac{1}{\sin^{2}{\left(x \right)}}$

The answer is:

$- \frac{1}{\sin^{2}{\left(x \right)}}$

The graph

Plot the graph f(x)

Plot the graph f'(x)

The first derivative [src]

        2   
-1 - tan (x)
------------
     2      
  tan (x)

$$\frac{- \tan^{2}{\left(x \right)} - 1}{\tan^{2}{\left(x \right)}}$$

Simplify

The second derivative [src]

                /            2   \
  /       2   \ |     1 + tan (x)|
2*\1 + tan (x)/*|-1 + -----------|
                |          2     |
                \       tan (x)  /
----------------------------------
              tan(x)

$$\frac{2 \left(\frac{\tan^{2}{\left(x \right)} + 1}{\tan^{2}{\left(x \right)}} - 1\right) \left(\tan^{2}{\left(x \right)} + 1\right)}{\tan{\left(x \right)}}$$

Simplify

The third derivative [src]

  /                                3                  2\
  |                   /       2   \      /       2   \ |
  |          2      3*\1 + tan (x)/    5*\1 + tan (x)/ |
2*|-2 - 2*tan (x) - ---------------- + ----------------|
  |                        4                  2        |
  \                     tan (x)            tan (x)     /

$$2 \left(- \frac{3 \left(\tan^{2}{\left(x \right)} + 1\right)^{3}}{\tan^{4}{\left(x \right)}} + \frac{5 \left(\tan^{2}{\left(x \right)} + 1\right)^{2}}{\tan^{2}{\left(x \right)}} - 2 \tan^{2}{\left(x \right)} - 2\right)$$

Simplify

The graph

Other calculators

How to use it?

Identical expressions

Similar expressions

Derivative of tan^-1x

The graph:

Piecewise:

The solution