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Derivative of sqrt(x^5-7)

Function f() - derivative -N order at the point
v

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Piecewise:

The solution

You have entered [src]
   ________
  /  5     
\/  x  - 7 
x57\sqrt{x^{5} - 7}
  /   ________\
d |  /  5     |
--\\/  x  - 7 /
dx             
ddxx57\frac{d}{d x} \sqrt{x^{5} - 7}
Detail solution
  1. Let u=x57u = x^{5} - 7.

  2. Apply the power rule: u\sqrt{u} goes to 12u\frac{1}{2 \sqrt{u}}

  3. Then, apply the chain rule. Multiply by ddx(x57)\frac{d}{d x} \left(x^{5} - 7\right):

    1. Differentiate x57x^{5} - 7 term by term:

      1. Apply the power rule: x5x^{5} goes to 5x45 x^{4}

      2. The derivative of the constant (1)7\left(-1\right) 7 is zero.

      The result is: 5x45 x^{4}

    The result of the chain rule is:

    5x42x57\frac{5 x^{4}}{2 \sqrt{x^{5} - 7}}

  4. Now simplify:

    5x42x57\frac{5 x^{4}}{2 \sqrt{x^{5} - 7}}


The answer is:

5x42x57\frac{5 x^{4}}{2 \sqrt{x^{5} - 7}}

The first derivative [src]
        4    
     5*x     
-------------
     ________
    /  5     
2*\/  x  - 7 
5x42x57\frac{5 x^{4}}{2 \sqrt{x^{5} - 7}}
The second derivative [src]
     /           5   \
   3 |        5*x    |
5*x *|2 - -----------|
     |      /      5\|
     \    4*\-7 + x //
----------------------
        _________     
       /       5      
     \/  -7 + x       
5x3(5x54(x57)+2)x57\frac{5 x^{3} \left(- \frac{5 x^{5}}{4 \left(x^{5} - 7\right)} + 2\right)}{\sqrt{x^{5} - 7}}
The third derivative [src]
      /         5           10   \
    2 |      5*x        25*x     |
15*x *|2 - ------- + ------------|
      |          5              2|
      |    -7 + x      /      5\ |
      \              8*\-7 + x / /
----------------------------------
              _________           
             /       5            
           \/  -7 + x             
15x2(25x108(x57)25x5x57+2)x57\frac{15 x^{2} \cdot \left(\frac{25 x^{10}}{8 \left(x^{5} - 7\right)^{2}} - \frac{5 x^{5}}{x^{5} - 7} + 2\right)}{\sqrt{x^{5} - 7}}