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Derivative of sin(n/6+2*x)

Function f() - derivative -N order at the point
v

The graph:

from to

Piecewise:

The solution

You have entered [src]
   /n      \
sin|- + 2*x|
   \6      /
$$\sin{\left(\frac{n}{6} + 2 x \right)}$$
sin(n/6 + 2*x)
Detail solution
  1. Let .

  2. The derivative of sine is cosine:

  3. Then, apply the chain rule. Multiply by :

    1. Differentiate term by term:

      1. The derivative of the constant is zero.

      2. The derivative of a constant times a function is the constant times the derivative of the function.

        1. Apply the power rule: goes to

        So, the result is:

      The result is:

    The result of the chain rule is:

  4. Now simplify:


The answer is:

The first derivative [src]
     /n      \
2*cos|- + 2*x|
     \6      /
$$2 \cos{\left(\frac{n}{6} + 2 x \right)}$$
The second derivative [src]
      /      n\
-4*sin|2*x + -|
      \      6/
$$- 4 \sin{\left(\frac{n}{6} + 2 x \right)}$$
The third derivative [src]
      /      n\
-8*cos|2*x + -|
      \      6/
$$- 8 \cos{\left(\frac{n}{6} + 2 x \right)}$$