Derivative of 7^x+e^x

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 x    x
7  + e

$$7^{x} + e^{x}$$

d / x    x\
--\7  + e /
dx

$$\frac{d}{d x} \left(7^{x} + e^{x}\right)$$

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Detail solution

Differentiate $7^{x} + e^{x}$ term by term:
1. $\frac{d}{d x} 7^{x} = 7^{x} \log{\left(7 \right)}$
2. The derivative of $e^{x}$ is itself.
The result is: $7^{x} \log{\left(7 \right)} + e^{x}$

The answer is:

$7^{x} \log{\left(7 \right)} + e^{x}$

The graph

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The first derivative [src]

 x    x       
e  + 7 *log(7)

$$7^{x} \log{\left(7 \right)} + e^{x}$$

Simplify

The second derivative [src]

 x    2       x
7 *log (7) + e

$$7^{x} \log{\left(7 \right)}^{2} + e^{x}$$

Simplify

The third derivative [src]

 x    3       x
7 *log (7) + e

$$7^{x} \log{\left(7 \right)}^{3} + e^{x}$$

Simplify

The graph