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Derivative of с^(sin(a*x+b))

Function f() - derivative -N order at the point
v

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The solution

You have entered [src]
 sin(a*x + b)
c            
$$c^{\sin{\left(a x + b \right)}}$$
c^sin(a*x + b)
Detail solution
  1. Let .

  2. Then, apply the chain rule. Multiply by :

    1. Let .

    2. The derivative of sine is cosine:

    3. Then, apply the chain rule. Multiply by :

      1. Differentiate term by term:

        1. The derivative of a constant times a function is the constant times the derivative of the function.

          1. Apply the power rule: goes to

          So, the result is:

        2. The derivative of the constant is zero.

        The result is:

      The result of the chain rule is:

    The result of the chain rule is:

  3. Now simplify:


The answer is:

The first derivative [src]
   sin(a*x + b)                    
a*c            *cos(a*x + b)*log(c)
$$a c^{\sin{\left(a x + b \right)}} \log{\left(c \right)} \cos{\left(a x + b \right)}$$
The second derivative [src]
 2  sin(b + a*x) /                   2                \       
a *c            *\-sin(b + a*x) + cos (b + a*x)*log(c)/*log(c)
$$a^{2} c^{\sin{\left(a x + b \right)}} \left(\log{\left(c \right)} \cos^{2}{\left(a x + b \right)} - \sin{\left(a x + b \right)}\right) \log{\left(c \right)}$$
The third derivative [src]
 3  sin(b + a*x) /        2             2                           \                    
a *c            *\-1 + cos (b + a*x)*log (c) - 3*log(c)*sin(b + a*x)/*cos(b + a*x)*log(c)
$$a^{3} c^{\sin{\left(a x + b \right)}} \left(\log{\left(c \right)}^{2} \cos^{2}{\left(a x + b \right)} - 3 \log{\left(c \right)} \sin{\left(a x + b \right)} - 1\right) \log{\left(c \right)} \cos{\left(a x + b \right)}$$