Mister Exam

Derivative of pisin(2pit/3)

Function f() - derivative -N order at the point
v

The graph:

from to

Piecewise:

The solution

You have entered [src]
      /2*pi*t\
pi*sin|------|
      \  3   /
πsin(2πt3)\pi \sin{\left(\frac{2 \pi t}{3} \right)}
pi*sin(((2*pi)*t)/3)
Detail solution
  1. The derivative of a constant times a function is the constant times the derivative of the function.

    1. Let u=2πt3u = \frac{2 \pi t}{3}.

    2. The derivative of sine is cosine:

      ddusin(u)=cos(u)\frac{d}{d u} \sin{\left(u \right)} = \cos{\left(u \right)}

    3. Then, apply the chain rule. Multiply by ddt2πt3\frac{d}{d t} \frac{2 \pi t}{3}:

      1. The derivative of a constant times a function is the constant times the derivative of the function.

        1. The derivative of a constant times a function is the constant times the derivative of the function.

          1. Apply the power rule: tt goes to 11

          So, the result is: 2π2 \pi

        So, the result is: 2π3\frac{2 \pi}{3}

      The result of the chain rule is:

      2πcos(2πt3)3\frac{2 \pi \cos{\left(\frac{2 \pi t}{3} \right)}}{3}

    So, the result is: 2π2cos(2πt3)3\frac{2 \pi^{2} \cos{\left(\frac{2 \pi t}{3} \right)}}{3}

  2. Now simplify:

    2π2cos(2πt3)3\frac{2 \pi^{2} \cos{\left(\frac{2 \pi t}{3} \right)}}{3}


The answer is:

2π2cos(2πt3)3\frac{2 \pi^{2} \cos{\left(\frac{2 \pi t}{3} \right)}}{3}

The graph
02468-8-6-4-2-1010-1010
The first derivative [src]
    2    /2*pi*t\
2*pi *cos|------|
         \  3   /
-----------------
        3        
2π2cos(2πt3)3\frac{2 \pi^{2} \cos{\left(\frac{2 \pi t}{3} \right)}}{3}
The second derivative [src]
     3    /2*pi*t\
-4*pi *sin|------|
          \  3   /
------------------
        9         
4π3sin(2πt3)9- \frac{4 \pi^{3} \sin{\left(\frac{2 \pi t}{3} \right)}}{9}
The third derivative [src]
     4    /2*pi*t\
-8*pi *cos|------|
          \  3   /
------------------
        27        
8π4cos(2πt3)27- \frac{8 \pi^{4} \cos{\left(\frac{2 \pi t}{3} \right)}}{27}