Mister Exam

Derivative of 1+cos2x

Function f() - derivative -N order at the point
v

The graph:

from to

Piecewise:

The solution

You have entered [src]
1 + cos(2*x)
cos(2x)+1\cos{\left(2 x \right)} + 1
1 + cos(2*x)
Detail solution
  1. Differentiate cos(2x)+1\cos{\left(2 x \right)} + 1 term by term:

    1. The derivative of the constant 11 is zero.

    2. Let u=2xu = 2 x.

    3. The derivative of cosine is negative sine:

      dducos(u)=sin(u)\frac{d}{d u} \cos{\left(u \right)} = - \sin{\left(u \right)}

    4. Then, apply the chain rule. Multiply by ddx2x\frac{d}{d x} 2 x:

      1. The derivative of a constant times a function is the constant times the derivative of the function.

        1. Apply the power rule: xx goes to 11

        So, the result is: 22

      The result of the chain rule is:

      2sin(2x)- 2 \sin{\left(2 x \right)}

    The result is: 2sin(2x)- 2 \sin{\left(2 x \right)}


The answer is:

2sin(2x)- 2 \sin{\left(2 x \right)}

The graph
02468-8-6-4-2-10105-5
The first derivative [src]
-2*sin(2*x)
2sin(2x)- 2 \sin{\left(2 x \right)}
The second derivative [src]
-4*cos(2*x)
4cos(2x)- 4 \cos{\left(2 x \right)}
The third derivative [src]
8*sin(2*x)
8sin(2x)8 \sin{\left(2 x \right)}
The graph
Derivative of 1+cos2x