1 -- 2 y
1/(y^2)
Let u=y2u = y^{2}u=y2.
Apply the power rule: 1u\frac{1}{u}u1 goes to −1u2- \frac{1}{u^{2}}−u21
Then, apply the chain rule. Multiply by ddyy2\frac{d}{d y} y^{2}dydy2:
Apply the power rule: y2y^{2}y2 goes to 2y2 y2y
The result of the chain rule is:
The answer is:
-2 ---- 2 y*y
6 -- 4 y
-24 ---- 5 y