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Derivative of (1/2)^x+1

Function f() - derivative -N order at the point
v

The graph:

from to

Piecewise:

The solution

You have entered [src]
 -x    
2   + 1
$$1 + \left(\frac{1}{2}\right)^{x}$$
(1/2)^x + 1
Detail solution
  1. Differentiate term by term:

    1. Let .

    2. Then, apply the chain rule. Multiply by :

      1. The derivative of a constant times a function is the constant times the derivative of the function.

        1. Apply the power rule: goes to

        So, the result is:

      The result of the chain rule is:

    3. The derivative of the constant is zero.

    The result is:


The answer is:

The graph
The first derivative [src]
  -x       
-2  *log(2)
$$- 2^{- x} \log{\left(2 \right)}$$
The second derivative [src]
 -x    2   
2  *log (2)
$$2^{- x} \log{\left(2 \right)}^{2}$$
The third derivative [src]
  -x    3   
-2  *log (2)
$$- 2^{- x} \log{\left(2 \right)}^{3}$$
3-я производная [src]
  -x    3   
-2  *log (2)
$$- 2^{- x} \log{\left(2 \right)}^{3}$$